Skip to main content
  1. Notes/
  2. IIT Madras Data Science/
  3. Calculus 1/

Calculus 1 Lecture 2.5: Finding Derivatives of Trigonometric Functions

3 mins
Calculus Mathematics
Table of Contents
Calculus-1 - This article is part of a series.
Part 2.5: This Article

The video “Calculus 1 Lecture 2.5: Finding Derivatives of Trigonometric Functions” by Professor Leonard explains how to derive and use the formulas for the derivatives of the six basic trigonometric functions: sine, cosine, tangent, secant, cosecant, and cotangent.


Explanation
#

1. Why Learn Trig Derivatives?
#

  • Trigonometric derivatives are used throughout calculus—especially in more advanced topics like substitution, solving differential equations, and solving real-world physics problems.
  • Memorizing the derivatives for all six trig functions (sine, cosine, tangent, cotangent, secant, cosecant) is crucial.

2. Proof of the Derivative of Sine
#

  • The video shows how the derivative of $\sin x$ is found using the limit definition of the derivative:

$$ \frac{d}{dx}[\sin x] = \lim_{h\to 0} \frac{\sin(x+h) - \sin(x)}{h} $$

  • The sine addition formula is used: $\sin(x + h) = \sin x \cos h + \cos x \sin h$.
  • After algebraic manipulation, limits, and trig limits ($\lim_{h \to 0} \sin h / h = 1$, $\lim_{h \to 0} (1 - \cos h)/h = 0$), the result is:

$$ \frac{d}{dx}[\sin x] = \cos x $$

  • Similarly, the derivative of $\cos x$ is $-\sin x$.

3. Derivatives of All Six Trig Functions
#

  • The derivatives of the other trig functions are derived using quotient and product rules, since:
    • $\tan x = \frac{\sin x}{\cos x}$ and so on.
  • The “memorization table” you need is:
    • $\frac{d}{dx}[\sin x] = \cos x$
    • $\frac{d}{dx}[\cos x] = -\sin x$
    • $\frac{d}{dx}[\tan x] = \sec^2 x$
    • $\frac{d}{dx}[\cot x] = -\csc^2 x$
    • $\frac{d}{dx}[\sec x] = \sec x \tan x$
    • $\frac{d}{dx}[\csc x] = -\csc x \cot x$

4. Examples Using Product and Quotient Rules
#

  • The video applies these formulas with the product rule (e.g., $y = x \sin x$), emphasizing recognizing when to use it.
    • For $y = x \sin x$: $y’ = x \cos x + \sin x$
  • When using quotient rule (e.g., derivatives involving ratios like $\frac{\sin x}{1 + \cos x}$), careful use of parentheses and step-by-step differentiation is demonstrated.

5. Higher-Order Derivatives and Oscillation
#

  • Repeatedly differentiating trigonometric functions (e.g., taking the second, third, fourth, etc., derivative of $\sin x$) results in a cyclical pattern due to the periodic nature of trig functions.
  • This relates to physical phenomena like oscillations (springs, pendulums), where derivatives describe velocity and acceleration in terms of position.

6. Physical Application Example
#

  • A spring/mass system oscillating is modeled as a cosine or sine function.
  • The derivative gives the velocity, and zeros of the derivative indicate turning points (maximum extension or compression of the spring).

7. Importance of Chain Rule
#

  • The video concludes by explaining the need for another differentiation technique, the chain rule, for handling compositions like $\sin(x^2)$ or more complex situations—this is presented as the next step in calculus after mastering trig, product, and quotient rules.

Summary
#

This lecture teaches how to find and use the derivatives of trigonometric functions. It shows:

  • The proofs using the limit definition and trig identities.
  • Memorization and application of all six derivatives.
  • How to use these derivatives in combination with product and quotient rules.
  • How derivatives cycle back to the function, reflecting periodic behavior.
  • The application to real-world oscillating systems and the transition into needing the chain rule.

Understanding and being able to use these derivatives is essential for success in calculus and in solving real-world and exam problems involving trigonometric functions. 1

Calculus-1 - This article is part of a series.
Part 2.5: This Article